Answer:
Steps:

1. Do the point slope form

Y-Y1=m(x-x1)

Y-5=2(x + 6)

Y-5=2x +12

2. Now you add 5 to the number 12

3. Your answer is

Y=2x +17

1. Do the point slope form

Y-Y1=m(x-x1)

Y-5=2(x + 6)

Y-5=2x +12

2. Now you add 5 to the number 12

3. Your answer is

Y=2x +17

Can anyone help me choose the correct answer?!

In the figure GHF =AEHD. Which statement is true by CPCTC?

Box A has a volume of 32 cubic meters. Box B is similar to box A. To create box B, box A's dimensions were tripled. What is the volume of box B? a. 864 m3 b. 288 m3 c. 96 m3 d. 32 m3

Life me kbhi sad mt hona kitne log agree hai

Find two numbers with a sum of 20 and a difference of 14.a. 4 and 18 b. –3 and –17 c. 2 and 16 d. 3 and 17

In the figure GHF =AEHD. Which statement is true by CPCTC?

Box A has a volume of 32 cubic meters. Box B is similar to box A. To create box B, box A's dimensions were tripled. What is the volume of box B? a. 864 m3 b. 288 m3 c. 96 m3 d. 32 m3

Life me kbhi sad mt hona kitne log agree hai

Find two numbers with a sum of 20 and a difference of 14.a. 4 and 18 b. –3 and –17 c. 2 and 16 d. 3 and 17

Add 5 to both sides

Multiply both sides by 5

Square both sides

Take the square root of both sides

*Here is your answer *

* x = 17.5*

*Make as brainliest plzz....*

*Hope this answer is helpful.*...

x-2y=2

3+y=6

I have a hard times putting graphs so I'll just put the answers and say how to graph with paper

so we notice that if we solve the second equation (3+y=6), we get a value for y and no value for x so just draw a horizonal line at the point 3 on the y axis

then make the second equation into slope inercept form y=mx+b

x-2y=2

2y-x=-2

2y=x+2

y=1/2x+1

just put in values for x and get y values, then plot points and get line

find where the line inercepts/crosses the first line (3+y=6) and that is the solution

OR

so a the solution is when both equations are true so just assume both are true and solve for x and y

x-2y=2

3+y=6

first of all the second equation is easy

3+y=6

subtract 3 from both sides

y=3

so we subsitute 3 for y in first equation

x-2(3)=2

x-6=2

add 6 to both sides

x=8

y=3

the solution is the point (8,3)

so we notice that if we solve the second equation (3+y=6), we get a value for y and no value for x so just draw a horizonal line at the point 3 on the y axis

then make the second equation into slope inercept form y=mx+b

x-2y=2

2y-x=-2

2y=x+2

y=1/2x+1

just put in values for x and get y values, then plot points and get line

find where the line inercepts/crosses the first line (3+y=6) and that is the solution

OR

so a the solution is when both equations are true so just assume both are true and solve for x and y

x-2y=2

3+y=6

first of all the second equation is easy

3+y=6

subtract 3 from both sides

y=3

so we subsitute 3 for y in first equation

x-2(3)=2

x-6=2

add 6 to both sides

x=8

y=3

the solution is the point (8,3)

Zero. An equilateral triangle has only 60 degree angles

**Answer:-5**

**Step-by-step explanation:**

2x+3=-7

2x=-7-3

x=-10/2

so,

x=-5

**Answer: x=-5**

**Step-by-step explanation: just did the assessment on edge**

**Answer: **

what? specify

I drew a picture, and unfortunately there isn't a way to upload it, so I'll just have to explain it to you.

DAB and BCD are opposite angles on a parallelogram, which makes that they are alternate interior angles when looking at it from a perspective of 2 parallel intersected lines. This means that DAB will have the same value as BCD, therefore BCD =**115 degrees**

DAB and BCD are opposite angles on a parallelogram, which makes that they are alternate interior angles when looking at it from a perspective of 2 parallel intersected lines. This means that DAB will have the same value as BCD, therefore BCD =